LSKMS svetaine - 2014 sudarymo cempionatas

2022 m. Lietuvos šaškių kompozicijų (100) čempionatas

Etiudų-100 skyrius. Papildomos pastabos

E03: The impurity 37/46 in variant Y₄ can be avoided by defining instead of that the variant Z₁ 45? (15?), 39(26), 33, 37(20), 42(25), 48 +.

E07: There is a small omission in variant B: (32-37), 2-13(36), 3(41), 36(47), 41, 13 +.

By the way this had no influence on the score given by me.

Besides I composed two endings on the same position (dia A) – both never published !

A B 2010-20B C 2010-20A (zaz)

Black moves, white wins

Diagram B (14-07-2010):

11(29A), 3933, 2(12BCD), 24(32EF), 42(17G), 24 (21), 9Z, 26(38), 48 +.

A (9), 12(31a), 22(36/37), 31, 8(31), 3(28A₁), 26(36), 37 +.

A₁ (36), 14(29), 32/37/46 +.

B (10), 47, 36(32), 4(24H), 10(38), 15(42/43), 47/49 +.

C (32), 42 +.

D (9), 42/47, 15 +.

E (43), 9, 49 +.

F (10), 5(43), 38 +.

G (18), 15(37), 1410(41), 47 +.

H (23), 15(28J), 42 +.

J (37), 10(29), 41/46(33), 32(39), 49 +.

Z 2?(9), 3(38), 26(43), 30(49Y) =.

Y (48?), 25 +.

a (32) and now 22 etc. + or 16(37), 32, 8(29), 3(2933), 17, 50 +.

Diagram C (13-07-2010):

(36A), 42, 2(12BCD), 24(32EF), 42(17G), 24 (21), 9Z, 26(38), 48 +.

A (32), 42(9), 12(36), 4137, 1(46A₁), 37, 23 +.

A₁ (47), 38, 23 +.

E08: I didn’t know the ML 1992 mini-ending to which Mr. V. Bieliauskas refers!

Variant G with impurity 32/46 not compositional: variant A already has the impurity 5/9-4 !

E15: Author’s solution not complete, because the variant 48(37AB), 23(21), 41/46(47), 19, 1930, 26 is surely worth to be defined.

E17: No solution after 2(25), 35(26), 8(28) =

E18: small deepening (JBas 25-03-2022)

3(23A), 47, 42(19B), 15(23), 20(37C), 14(29), 41/46(33), 32(39), 49 +.

A (22), 21 P.Rimsa 2022: (37D), 41/46(42), 37, 26(36), 37 +.

B (20), 15(37), 47 +.

C (28), 42 +.

D (27), 17(33), 39(37), 41/46(42), 37, 28 +.

Johan Bastiaannet